document.write( "Question 388273: 2.mr. ong makes regular business trips to kaulalumpur a distance of 420 km from singapore (a)on his way up to kaulalumpur he travels along the trunk road at an average speed of x km/h. write down the expression in trm of x for the time taken in hours to travel from singapore to kaulalumpur
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document.write( "(b)on his return journey to singapore he travels along the north south highway and increases the average speed by 15 km/h.write down the expression in term of x for the time taken in the hours to travel from kaulalumpur to singapore.
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document.write( "(c)if the time difference between the two journey is 40 min from an equation in x and show that it reduces x^2+15x-9540=0
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document.write( "(d)solve the equation and find the time taken for the trip from singapore to kaulalampur \n" );
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Algebra.Com's Answer #274691 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 2.mr. ong makes regular business trips to kaulalumpur a distance of 420 km from singapore (a)on his way up to kaulalumpur he travels along the trunk road at an average speed of x km/h. write down the expression in trm of x for the time taken in hours to travel from singapore to kaulalumpur \n" ); document.write( "(b)on his return journey to singapore he travels along the north south highway and increases the average speed by 15 km/h.write down the expression in term of x for the time taken in the hours to travel from kaulalumpur to singapore. \n" ); document.write( "(c)if the time difference between the two journey is 40 min from an equation in x and show that it reduces x^2+15x-9540=0 \n" ); document.write( "(d)solve the equation and find the time taken for the trip from singapore to kaulalampur \n" ); document.write( "... \n" ); document.write( "FORWARD \n" ); document.write( "speed x km/h \n" ); document.write( "distance = 420 km\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "t=d/r \n" ); document.write( "t= 420/x hours \n" ); document.write( "... \n" ); document.write( "RETURN \n" ); document.write( "------- \n" ); document.write( "speed = x+15 km/h \n" ); document.write( "distance = 420 km \n" ); document.write( ".. \n" ); document.write( "time = 420/(x+15) hours. \n" ); document.write( "... \n" ); document.write( "40 minutes = 40/60 = 2/3 \n" ); document.write( "time going - time returning = 2/3 hours \n" ); document.write( "(420/x)-420/(x+15)=3/4 \n" ); document.write( "... \n" ); document.write( "LCD = x(x+15) \n" ); document.write( "multiply equation by x(x+15) \n" ); document.write( "420(x+15)-420x=2/3* x(x+15) \n" ); document.write( "420x+6300-420x=2/3*x(x+15) \n" ); document.write( "6300=2/3*x(x+15) \n" ); document.write( "multiply by3 \n" ); document.write( "18900=2x^2+30x \n" ); document.write( "2x^2+30x-18,900=0 \n" ); document.write( "/2 \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "x^2+15x-9450=0 \n" ); document.write( "x^2+105x-90x-9450=0 \n" ); document.write( "x(x+105)-90(x+105)=0 \n" ); document.write( "(x+105)(x-90)=0 \n" ); document.write( "x= 90 km/h \n" ); document.write( "... \n" ); document.write( "distance = 420 km \n" ); document.write( "speed = 90 km/h \n" ); document.write( "time = 420/90 \n" ); document.write( " \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |