document.write( "Question 388376: the width of a rectangle is two meters more then one third of the length. The perimeter of the rectangle is forty four meters. Find the measure of each angle.
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Algebra.Com's Answer #274688 by mananth(16946) $\"\"$ $\"About$

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the width of a rectangle is two meters more then one third of the length. The perimeter of the rectangle is forty four meters. Find the measure of each angle.
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\n" ); document.write( "let length = l
\n" ); document.write( "l/3 +2 = width
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\n" ); document.write( "2*(l+w)=perimeter
\n" ); document.write( "2*(l+l/3+2)=40
\n" ); document.write( "/2
\n" ); document.write( "l+l/3 +2 = 20
\n" ); document.write( "l+l/3 = 20-2
\n" ); document.write( "l+l/3 = 18
\n" ); document.write( "4l/3=18
\n" ); document.write( "multiply by 3
\n" ); document.write( "4l = 18*3
\n" ); document.write( "41=54
\n" ); document.write( "/4
\n" ); document.write( "l = 54/4
\n" ); document.write( "l=13.5 meters ---- The length
\n" ); document.write( "width = (1/3*13.5) +2
\n" ); document.write( "width = 6.5 meters
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\n" ); document.write( "CHECK
\n" ); document.write( "2*(13.5+6.5)=
\n" ); document.write( "2*(20)=40 meters
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\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "

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