document.write( "Question 388384: 2y^2 - 3y + 1 = ( )( ) \n" ); document.write( "
Algebra.Com's Answer #274681 by mananth(16946)\"\" \"About 
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2y^2 - 3y + 1 \r
\n" ); document.write( "\n" ); document.write( "2y^2-2y-y+1
\n" ); document.write( "2y(y-1)-1(y-1)
\n" ); document.write( "= ( y-1)( 2y-1 )
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca
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