document.write( "Question 388323: what is the base area and height of a rectangle whose perimeter is 44in and the base is two less than three times the height. \n" ); document.write( "

Algebra.Com's Answer #274623 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,         
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document.write( "Let x and (3x-2in) represent the height and base respectively,
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document.write( "Question states***
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document.write( "Perimeter = 44in = x + x +(3x-2in) + (3x-2in)
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document.write( " 44in = x + x +(3x-2in) + (3x-2in)
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document.write( "solving for x
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document.write( " 44in = 8x - 4in
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document.write( " 48in = 8x
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document.write( "  6 = x, 6in is the height, the base is 16in     (18in-2in)\r
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document.write( "CHECKING our Answer
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document.write( " 2*6in + 2*16in = 12in + 32in = 44in \n" );
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