document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388289>Question 388289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I prove the theorem \"Through a given point of a given line there is only one plane perpendicular to the line\"? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274594 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274594\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can prove the converse, that the vector normal (you use perpendicular, not exactly the same) to a plane is unique in direction.  Then any line parallel to the vector thru a chosen point is normal to the plane, and not normal to any plane not parallel to the given plane.<BR>\n" );
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document.write( "As an alternative, choose a point on a line in 3-space.  Find 2 lines not 180º apart perpendicular to the 1st line.  Those 2 lines define a plane.<BR>\n" );
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