document.write( "Question 388279: how much 20% antifreeze solution must be mixed 2with a 80% solution to ptoduce 20 gallons of a 65% disinfecant solution \n" ); document.write( "

Algebra.Com's Answer #274579 by Fombitz(32388) $\"\"$ $\"About$

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Let A be the amount of 20% solution, let B be the amount of 80% solution.
\n" ); document.write( "1. $\"A%2BB=20\"$
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\n" ); document.write( " $\"20A%2B80B=65%2820%29\"$
\n" ); document.write( "2. $\"A%2B4B=65\"$
\n" ); document.write( "Subtract eq. 1 from eq. 2,
\n" ); document.write( " $\"A%2B4B-A-B=65-20\"$
\n" ); document.write( " $\"3B=45\"$
\n" ); document.write( " $\"highlight%28B=15%29\"$ gallons
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( " $\"A%2B15=20\"$
\n" ); document.write( " $\"highlight%28A=5%29\"$ gallons \n" ); document.write( "

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