document.write( "Question 5378: The petty-cash drawer of a small office contained $16.25. If there were twice as many nickels as quarters and as many dimes as nickels and quarters combined; how many coins of each type were there? \n" ); document.write( "
Algebra.Com's Answer #2745 by Abbey(339)\"\" \"About 
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Let x = the number of quarters
\n" ); document.write( "Let 2x = number of nickels (twice as many as quarters)
\n" ); document.write( "Let (2x+x) = the number of dimes (as many dimes as quarters and nickels combined)
\n" ); document.write( "Let's work in cents, rather than dollars for this equation:\r
\n" ); document.write( "\n" ); document.write( "Total value = 1,625 cents\r
\n" ); document.write( "\n" ); document.write( "The total value of each of these coins is determined by multiplying the value by the number of coins (If I have two nickels worth 5 cents, then 2*5=10 - I have 10 cents worth of coins):\r
\n" ); document.write( "\n" ); document.write( "let 5(2x) = the total value of nickels
\n" ); document.write( "let 10(2x+x) = the total value of dimes
\n" ); document.write( "let 25x = the total value of quarters\r
\n" ); document.write( "\n" ); document.write( "Total value = value of nickels + value of dimes + value of quarters
\n" ); document.write( "1625 = 5(2x) + 10(2x+x) + 25x
\n" ); document.write( "1625 = 10x + (20x+10x) + 25x
\n" ); document.write( "1625 = 65x
\n" ); document.write( "divide both sides by 65
\n" ); document.write( "25 = x\r
\n" ); document.write( "\n" ); document.write( "So the number of quarters = 25
\n" ); document.write( "The number of nickels is twice that, or 50
\n" ); document.write( "and the number of dimes is the same as the nickels and quarters, or 75\r
\n" ); document.write( "\n" ); document.write( "Check by looking at the values:
\n" ); document.write( "25 quarters = $6.25
\n" ); document.write( "50 nickels = $2.50
\n" ); document.write( "75 dimes = $7.50\r
\n" ); document.write( "\n" ); document.write( "6.25 + 2.5 +7.5 = 16.25\r
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