document.write( "Question 388168: the denominator of the fraction is 2 more than the numerator. if 1 is subtracted from both numerator and denominator, the resulting fraction has a value of 1/2. find the original fraction \n" ); document.write( "
Algebra.Com's Answer #274466 by aggie_tutor(13)\"\" \"About 
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Let numerator = x
\n" ); document.write( "Problem statment: demoninator = (x+2)
\n" ); document.write( "So the fraction looks like:
\n" ); document.write( "x/(x+2)\r
\n" ); document.write( "\n" ); document.write( "Second part of problem statement:
\n" ); document.write( "Numerator (x-1)
\n" ); document.write( "Denominator (x+2)-1\r
\n" ); document.write( "\n" ); document.write( "So the new fraction (forget about the old one!) looks like:
\n" ); document.write( "\"%28x-1%29%2F%28x%2B2-1%29\"\r
\n" ); document.write( "\n" ); document.write( "For subtraction simplifies to:
\n" ); document.write( "\"%28x-1%29%2F%28x%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "Set the equation. Problem statement says this fraction thing is equal to 1/2.
\n" ); document.write( "\"%28x-1%29%2F%28x%2B1%29+=+1%2F2\"\r
\n" ); document.write( "\n" ); document.write( "The 1/2 fraction doesn't look too nice so let's just make it 1. We can do that by multiplying both sides of the equation by 2, i.e. 2/1.\r
\n" ); document.write( "\n" ); document.write( "\"%282%2F1%29%28%28x-1%29%2F%28x%2B1%29%29+=+%282%2F1%29%281%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "The right side just becomes 1 (the 2s cancel out.)
\n" ); document.write( "The left side is tricky. You must multiply the numerator by 2 only.
\n" ); document.write( "\"%282%29%2A%28x-1%29\" becomes \"2x-2\"
\n" ); document.write( "
\n" ); document.write( "The denominator is multiplied by 1, so it does not change at all.
\n" ); document.write( "The new left side and right side of the equation is now:
\n" ); document.write( "\"%282x-2%29%2F%28x%2B1%29+=+1\"\r
\n" ); document.write( "\n" ); document.write( "Much nicer to look at. And when we have a fraction = 1, we can always multiply both sides by the denominator (x+1). This cancels the denominator on the left, and moves the (x+1) to the right side. This gets rid of the fraction, which is what we wanted.
\n" ); document.write( "\"%28x%2B1%29%28%282x-2%29%2F%28x%2B1%29%29+=+%28x%2B1%29%281%29\"
\n" ); document.write( "\"%282x-2%29+=+%28x%2B1%29\"
\n" ); document.write( "\"2x-2+=+x%2B1\"
\n" ); document.write( "Combine like terms. We can put x terms on the left, and the constant (non-x) terms on the right. First subtract x from both sides.
\n" ); document.write( "\"2x-2-x+=+x-x%2B1\"
\n" ); document.write( "\"x-2+=+1\"
\n" ); document.write( "Now add 2 to both sides.
\n" ); document.write( "\"x-2%2B2+=+1%2B2\"
\n" ); document.write( "\"x+=+3\"\r
\n" ); document.write( "\n" ); document.write( "Check your answer by putting x into the original equation.
\n" ); document.write( "\"%28x-1%29%2F%28x%2B1%29+=+1%2F2\"
\n" ); document.write( "\"%283-1%29%2F%283%2B1%29+=+1%2F2\"
\n" ); document.write( "\"%282%29%2F%284%29+=+1%2F2\"\r
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