document.write( "Question 388162: HOW DO I GRAPH THE EQUTION y+x=14 \n" ); document.write( "
Algebra.Com's Answer #274462 by avani(25)\"\" \"About 
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y+x=14
\n" ); document.write( "y=-x+14\r
\n" ); document.write( "\n" ); document.write( "•X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 14/1 = 14.
\n" ); document.write( "•Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 14/1 = 14.
\n" ); document.write( "•Slope is -1/1 = -1.
\n" ); document.write( "•Equation in slope-intercept form: y=-1*x+14\r
\n" ); document.write( "\n" ); document.write( "points are:-
\n" ); document.write( "(x,y)form
\n" ); document.write( "when y=0, x=14 (14,0)
\n" ); document.write( "when x=0, y=14 (0,14)
\n" ); document.write( "when x=1, y=-1+14=13 (1,13)
\n" ); document.write( "when x=2, y=-2+14=12 (2,12)\r
\n" ); document.write( "\n" ); document.write( "and so on...\r
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\n" ); document.write( "\n" ); document.write( "to lear more go here
\n" ); document.write( "http://www.math.com/school/subject2/lessons/S2U4L3DP.html
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