document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41721>Question 41721</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the properties of Logarithms to evaluate:<BR>\n" );
document.write( "Log sub3 9+Log sub3 36-log sub3 4. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27442 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay from<BR>\n" );
document.write( "log(3) 9 + log(3) 36 - log(3) 4 =<BR>\n" );
document.write( "we multiply numbers when we add logs and divide when we subtract logs, so we have<BR>\n" );
document.write( "log(3) (9 * 36 ÷ 4) =<BR>\n" );
document.write( "log(3) 81 =<BR>\n" );
document.write( "4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );