document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=388085>Question 388085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sean is five years older than peter. if the sum of their ages is at most 37 years, what is the olders that peter can be </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274418 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274418\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = sean's age.<BR>\n" );
document.write( "x - 5 = peter's age.\r<BR>\n" );
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document.write( "x + x-5 <= 37\r<BR>\n" );
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document.write( "combine like terms to get:\r<BR>\n" );
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document.write( "2x - 5 <= 37\r<BR>\n" );
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document.write( "add 5 to both sides to get:\r<BR>\n" );
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document.write( "2x <= 42\r<BR>\n" );
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document.write( "divide both sides by 2 to get:\r<BR>\n" );
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document.write( "x <= 21\r<BR>\n" );
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document.write( "peter's age is x-5\r<BR>\n" );
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document.write( "the oldest peter can be is 21-5 = 16\r<BR>\n" );
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document.write( "when peter = 16, sean = 16 + 5 = 21\r<BR>\n" );
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document.write( "21 + 16 = 37\r<BR>\n" );
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document.write( " </SPAN>\n" );
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