document.write( "Question 388069: Elvira made a trip on Tuesday, and David made the same trip on Wednesday. Elvira traveled at 14 mph. David traveled at 21 mph, so his time was 3 hours less than Elvira's time. How far did they travel? \n" ); document.write( "
Algebra.Com's Answer #274389 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Let x and (x-3) represent Elvira's and David's times respectively
\n" ); document.write( "D = r*t
\n" ); document.write( "Distances traveled are equal in this example***
\n" ); document.write( " 14mph*x = 21mph(x-3)
\n" ); document.write( "solving for x
\n" ); document.write( " 14x = 21x - 63
\n" ); document.write( " 63 = 7x
\n" ); document.write( "x = 9hr, the time that Elvira traveled. David traveled 6hrs (9hr-3hr = 6hr)\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 14mph*9hr = 126mi = 21mph*6hr = 126mi \n" ); document.write( "
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