document.write( "Question 388044: how many seconds will the ball be 75 ft haigh after hit 2 feet off the ground and initial upward velocity of 90 ft / sec.\r
\n" );
document.write( "\n" );
document.write( "75h = 2 ho + 90 t - 16 t squared \n" );
document.write( "
Algebra.Com's Answer #274383 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! how many seconds will the ball be 75 ft haigh after hit 2 feet off the ground and initial upward velocity of 90 ft / sec. \n" ); document.write( "75h = 2 ho + 90 t - 16 t squared \n" ); document.write( "----------------- \n" ); document.write( "h(t) = -16t^2 + 90t + 2 \n" ); document.write( "At h = 75: \n" ); document.write( "-16t^2 + 90t + 2 = 75 \n" ); document.write( "-16t^2 + 90t - 73 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "---------------------- \n" ); document.write( "The ball passes 75 feet twice, ascending at t = 0.982839853961944, and descending at t = 4.64216014603806 seconds. \n" ); document.write( "------------------- \n" ); document.write( "The ball is exactly 75 feet high for zero time, or dt seconds. \n" ); document.write( "It is at or above 75 feet for the difference between the 2 times above, \n" ); document.write( "=~ 3.659 seconds\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |