document.write( "Question 42308: BOB & MARY EACH HAVE APPLES
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document.write( "IF BOB WERE TO GIVE MARY 2 OF HIS APPLES MARY WOULD HAVE TWICE AS MANY APPLES AS BOB. HOWEVER, IF MARY WERE TO GIVE BOB 2 OF HER APPLES, BOTH MARY AND BOB WOULD HAVE THE SAME NUMBER OF APPLES. HOW MANY APPLES DOES BOB AND MARY TO START? \n" );
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Algebra.Com's Answer #27438 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Let b and m be what Bob and Mary have before giving any of them away. \n" ); document.write( "The first statement says \n" ); document.write( "2(b - 2) = m + 2 \n" ); document.write( "The second says \n" ); document.write( "m - 2 = b + 2 \n" ); document.write( "Solve both for m and set them equal...we have \n" ); document.write( "2b - 4 = m + 2 \n" ); document.write( "m = 2b - 6 \n" ); document.write( "and \n" ); document.write( "m = b + 4 \n" ); document.write( "so that \n" ); document.write( "2b - 6 = b + 4 \n" ); document.write( "and you can find that \n" ); document.write( "b = 10 \n" ); document.write( "and \n" ); document.write( "m = 14 \n" ); document.write( "and you can check that it is true by plugging these numbers into the problem... \n" ); document.write( " |