document.write( "Question 387941: A clothing store owner knows from previous records that any person who comes into her store has a 60 percent chance of making a purchase. She notes that there are 13 people in her store at the current time. What is the probability that:\r
\n" ); document.write( "\n" ); document.write( "a. exactly 5 people will make a purchase?
\n" ); document.write( "b. less than 8 people make a purchase?
\n" ); document.write( "c. More than 10 people make a purchase?
\n" ); document.write( "

Algebra.Com's Answer #274352 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "Note: The probability of x successes in n trials is: P = nCx* \"p%5Ex%2Aq%5E%28n-x%29\"
\n" ); document.write( " where p and q are the probabilities of success and failure respectively.
\n" ); document.write( "In this case p =.6 and q = .4
\n" ); document.write( "nCx = \"n%21%2F%28x%21%28n-x%21%29%29\"
\n" ); document.write( "for example:
\n" ); document.write( "P(exactly 5 people will make a purchase)= 1287(.6)^5(.4)^8 = .06559\r
\n" ); document.write( "\n" ); document.write( "P(less than 8 people make a purchase)
\n" ); document.write( "1- P(8) - P(9) - P(10) - P(11)- P(12) - P(13) = .4256 (Stat Trek)\r
\n" ); document.write( "\n" ); document.write( "P(More than 10 people make a purchase) = P(11) + P(12) + P(13)
\n" ); document.write( " P(11) + P(12) + P(13) = .04528 + .01132 + .00131 = .0579 \n" ); document.write( "
\n" );