document.write( "Question 388029: Find the radius of the circle defined by the equation: x^2+y^2-10x+4y+4=0. \n" ); document.write( "
Algebra.Com's Answer #274338 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
Recall the equation of a circle:\r
\n" ); document.write( "\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2+=+r%5E2+\"where (h,k) is the circle's center and \"r+\"is the radius.\r
\n" ); document.write( "\n" ); document.write( "In this problem, we need to complete the square to get the equation in the above form.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+y%5E2+-+10x+%2B+4y+%2B+4+=+0\".......you just need to realize that you take half of the linear term (x and y)\r
\n" ); document.write( "\n" ); document.write( "\"%28x-5%29%5E2+-+25%2B%28y%2B2%29%5E2+-+4+=+-4+\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-5%29%5E2+%2B%28y%2B2%29%5E2+=+-4+%2B+25+%2B+4\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-5%29%5E2+%2B%28y%2B6%29%5E2+=25\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-5%29%5E2+%2B%28y%2B6%29%5E2+=+5%5E2\"...............\"r%5E2=5%5E2\"...>....\"r=5\"\r
\n" ); document.write( "\n" ); document.write( "It's obvious from above that the center of the circle is (5,-2) and radius is \"5\".\r
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Solved by pluggable solver: PLOT any circle and describe it

\n" ); document.write( " Diameter: \"d+=+2r+=+2%2A5+=+10\".
\n" ); document.write( " Area: \"area+=+pi%5Cr%5E2+=+pi%2A5%5E2+=+78.5398173497349\"
\n" ); document.write( " Perimeter: \"perimeter+=+2%5Cpi%5Cr+=+2%5Cpi%2A5+=+31.415926939894\"
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