document.write( "Question 388025: Find the center of a circle defined by the equation: x^2+y^2-10x+12y+12=0. \n" ); document.write( "

Algebra.Com's Answer #274334 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Standard Form of an Equation of a Circle is 
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document.write( "where Pt(h,k) is the center
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document.write( "x^2+y^2-10x+12y+12=0
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document.write( "completing the squares to put into the Standard Form
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document.write( "x^2 -10x + y^2 +12y + 12 = 0
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document.write( " (x-5)^2 - 25 + (y+6)^2 - 36 + 12 = 0
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document.write( "  (x-5)^2 + (y+6)^2 -49 = 0
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document.write( "  (x-5)^2 + (y+6)^2 = 49 
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document.write( "Center (5,-6)  radius = 7
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