document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387998>Question 387998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/4 of this seniors have averages above 90. 1/2 of the remainders have averages between 80 and 90. what part of the senior class have averages below 80? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274294 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274294\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/4 of the seniors have averages above 90.<BR>\n" );
document.write( "The remainder is 3/4 of the seniors.<BR>\n" );
document.write( "1/2 of the remainders have averages between 80 and 90.<BR>\n" );
document.write( "That means that 1/2 * 3/4 of the seniors have averages between 80 and 90.<BR>\n" );
document.write( "That means that 3/8 of the seniors have averages between 80 and 90.<BR>\n" );
document.write( "The total number of seniors that have averages above 80 is equal to 1/4 + 3/8.<BR>\n" );
document.write( "Since 1/4 = 2/8, then the total number of seniors that have averages above 80 is equal to 5/8.<BR>\n" );
document.write( "That leaves 3/8 of the seniors that have averages below 80 because 5/8 + 3/8 = 8/8 = 1.\r<BR>\n" );
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