document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387865>Question 387865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A charter flight charges its members $400 per year. But for evry new member in excessof 60 the charge for every member is reduced by $5. What number of members leads to maximum revenue? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274285 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = # of members in excess of 60.<BR>\n" );
document.write( "Then for x members in excess of 60, the total number of members is 60 + x, while the unit price is 400 - 5x.  The  revenue is then <BR>\n" );
document.write( "(60 + x)(400 - 5x), a quadratic expression.  The value of x that would maximize the revenues would be the midway between the x-intercepts, or (-60 + 80)/2 = 20/2 = 10.  Hence 70 members would maximize revenues. </SPAN>\n" );
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