document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387964>Question 387964</A>: <I><SPAN STYLE=\"word-break: break-all;\"> train a and b are traveling the same direction on parallel tracks. Train a is traveling at a rate of 100mph and train b at 125mph. Train a passes a station at 6:10am and train b passes the same station at 6;22am what time will train b catch up to train a? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274262 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274262\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> train A has a 12 min (6:22 - 6:10) head start , or 1/5 hr (12 / 60)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "at 100 mph , 1/5 hr means a 20 mi head start (100 mph * 1/5 hr)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "train B is catching up at 25 mph (125 mph - 100 mph)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "it takes train B 4/5 hr to catch up (20 mi / 25 mph) , this is 48 min (4/5 * 60)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "so B catches A at 7:10 (6:22 + 0:48) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );