document.write( "Question 387953: I am trying to find the y-intercept, as an ordered pair, of the equation $\"+x=3y%5E2%2B12y%2B6+\"$ . I have tried solving it myself by making \"x\" equal to 0 and then I simplified the equation to $\"+-%281%2F6%29=y%5E2%2By+\"$ , and I was unsure as to what to do after that, or if that was even right. Thank you, and if there was any way that you could show me the steps you took that would be great. Thanks again. \n" ); document.write( "

Algebra.Com's Answer #274251 by 533908(1) $\"\"$ $\"About$

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$\"+x=3y%5E2%2B12y%2B6+\"$
\n" ); document.write( "Yes, set x = 0:
\n" ); document.write( " $\"+0=3y%5E2%2B12y%2B6+\"$
\n" ); document.write( "divide both sides by 3:
\n" ); document.write( " $\"+0=y%5E2%2B4y%2B2+\"$
\n" ); document.write( "Since you can't factor you must resort to the quadratic formula. Doing so, yields:
\n" ); document.write( "y = {-0.586, -3.414}
\n" ); document.write( "so, the y-intercepts are at:
\n" ); document.write( "(0, -0.586) and (0, -3.414)
\n" ); document.write( ". \n" ); document.write( "

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