document.write( "Question 387898: B is due east of A. if they walk directly toward each other, they meet with each other after 2 hour.if they both walk east at constant speed, A will catch up to B after 10 hour. if they both walk west at constant speed, A will walk 30 km before B reaches A's home.
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document.write( "=>What is the distance between A and B's home?
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document.write( "=>What is each of their speed? \n" );
document.write( "
Algebra.Com's Answer #274250 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! B is due east of A. if they walk directly toward each other, they meet with each other after 2 hour.if they both walk east at constant speed, A will catch up to B after 10 hour. if they both walk west at constant speed, A will walk 30 km before B reaches A's home. \n" ); document.write( ": \n" ); document.write( "=>What is the distance between A and B's home? \n" ); document.write( "Let d = distance from A to B \n" ); document.write( ": \n" ); document.write( "Let a = A's speed \n" ); document.write( "Let b = B's speed \n" ); document.write( ": \n" ); document.write( "\"if they walk directly toward each other, they meet with each other after 2 hour.\" \n" ); document.write( "Write a distance equation from this statement: \n" ); document.write( "d = 2a + 2b \n" ); document.write( ": \n" ); document.write( "\"if they both walk east at constant speed, A will catch up to B after 10 hour.\" \n" ); document.write( "Write a distance equation \n" ); document.write( "10a - d = 10b \n" ); document.write( "Replace d with (2a+2b) \n" ); document.write( "10a -(2a+2b) = 10b \n" ); document.write( "10a - 2a - 2b = 10b \n" ); document.write( "10a - 2a = 10b + 2b \n" ); document.write( "8a = 12b \n" ); document.write( "Simplify, divide by 4 \n" ); document.write( "2a = 3b \n" ); document.write( "a = 1.5b \n" ); document.write( ": \n" ); document.write( "\"if they both walk west at constant speed, A will walk 30 km before B reaches A's home. \n" ); document.write( "Write a time equation: Time = dist/speed \n" ); document.write( "A's time = B's time \n" ); document.write( " \n" ); document.write( "Replace a with 1.5b \n" ); document.write( " \n" ); document.write( "Cancel 1.5 into 30 \n" ); document.write( " \n" ); document.write( "Multiply both sides by b \n" ); document.write( "20 = d \n" ); document.write( "d = 20 km is the distance between A & B \n" ); document.write( ": \n" ); document.write( "=>What is each of their speed? \n" ); document.write( ": \n" ); document.write( "2a + 2b = 20 \n" ); document.write( "Simplify divide by 2 \n" ); document.write( "a + b = 10 \n" ); document.write( "Replace a with 1.5b \n" ); document.write( "1.5b + b = 10 \n" ); document.write( "2.5b = 10 \n" ); document.write( "b = \n" ); document.write( "b = 4 km/hr is B's speed \n" ); document.write( "then \n" ); document.write( "a = 1.5(4) = 6 km/hr is A's speed \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |