document.write( "Question 387898: B is due east of A. if they walk directly toward each other, they meet with each other after 2 hour.if they both walk east at constant speed, A will catch up to B after 10 hour. if they both walk west at constant speed, A will walk 30 km before B reaches A's home.
\n" ); document.write( "=>What is the distance between A and B's home?
\n" ); document.write( "=>What is each of their speed?
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Algebra.Com's Answer #274250 by ankor@dixie-net.com(22740)\"\" \"About 
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B is due east of A. if they walk directly toward each other, they meet with each other after 2 hour.if they both walk east at constant speed, A will catch up to B after 10 hour. if they both walk west at constant speed, A will walk 30 km before B reaches A's home.
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\n" ); document.write( "=>What is the distance between A and B's home?
\n" ); document.write( "Let d = distance from A to B
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\n" ); document.write( "Let a = A's speed
\n" ); document.write( "Let b = B's speed
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\n" ); document.write( "\"if they walk directly toward each other, they meet with each other after 2 hour.\"
\n" ); document.write( "Write a distance equation from this statement:
\n" ); document.write( "d = 2a + 2b
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\n" ); document.write( "\"if they both walk east at constant speed, A will catch up to B after 10 hour.\"
\n" ); document.write( "Write a distance equation
\n" ); document.write( "10a - d = 10b
\n" ); document.write( "Replace d with (2a+2b)
\n" ); document.write( "10a -(2a+2b) = 10b
\n" ); document.write( "10a - 2a - 2b = 10b
\n" ); document.write( "10a - 2a = 10b + 2b
\n" ); document.write( "8a = 12b
\n" ); document.write( "Simplify, divide by 4
\n" ); document.write( "2a = 3b
\n" ); document.write( "a = 1.5b
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\n" ); document.write( "\"if they both walk west at constant speed, A will walk 30 km before B reaches A's home.
\n" ); document.write( "Write a time equation: Time = dist/speed
\n" ); document.write( "A's time = B's time
\n" ); document.write( "\"30%2Fa\" = \"d%2Fb\"
\n" ); document.write( "Replace a with 1.5b
\n" ); document.write( "\"30%2F1.5b\" = \"d%2Fb\"
\n" ); document.write( "Cancel 1.5 into 30
\n" ); document.write( "\"20%2Fb\" = \"d%2Fb\"
\n" ); document.write( "Multiply both sides by b
\n" ); document.write( "20 = d
\n" ); document.write( "d = 20 km is the distance between A & B
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\n" ); document.write( "=>What is each of their speed?
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\n" ); document.write( "2a + 2b = 20
\n" ); document.write( "Simplify divide by 2
\n" ); document.write( "a + b = 10
\n" ); document.write( "Replace a with 1.5b
\n" ); document.write( "1.5b + b = 10
\n" ); document.write( "2.5b = 10
\n" ); document.write( "b = \"10%2F2.5\"
\n" ); document.write( "b = 4 km/hr is B's speed
\n" ); document.write( "then
\n" ); document.write( "a = 1.5(4) = 6 km/hr is A's speed
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