document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387891>Question 387891</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two times a first number decreased by a second number is 4. The first number increased by twice the second number is 37. Find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274241 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"Two times a first number decreased by a second number is 4\" ___ 2f - s = 4\r<BR>\n" );
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document.write( "\"The first number increased by twice the second number is 37\" ___ f + 2s = 37\r<BR>\n" );
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document.write( "multiplying 1st eqn by 2 ___ 4f - 2s = 8\r<BR>\n" );
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document.write( "adding 2nd eqn (eliminating s)___ 5f = 45 ___ f = 9\r<BR>\n" );
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document.write( "substituting to find s ___ 2(9) - s = 4 ___ 14 = s </SPAN>\n" );
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