document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387876>Question 387876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bicyclist leaves Bay Shore traveling at an average speed of 12 miles per hour. <BR>\n" );
document.write( "Three hours later, a car leaves Bay Shore, on the same route, traveling at an <BR>\n" );
document.write( "average speed of 30 miles per hour. How many hours after the car leaves Bay <BR>\n" );
document.write( "Shore will the car catch up to the cyclist? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274228 by </B><A HREF=/tutors/aboutme.mpl?userid=jrfrunner><B>jrfrunner(365)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jrfrunner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jrfrunner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274228\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> car will catch up to the bike when <BR>\n" );
document.write( "the distance for the car = distance for the bike<BR>\n" );
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document.write( "distance =rate * time<BR>\n" );
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document.write( "distance bike= head start distance + distance after car leaves<BR>\n" );
document.write( "             = 12mph*3 hours + 12mph*t = 36+12t<BR>\n" );
document.write( "distance car=30mph * t<BR>\n" );
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document.write( "set distance bike=distance car<BR>\n" );
document.write( "36+12t=30t<BR>\n" );
document.write( "36=18t<BR>\n" );
document.write( "36/18=2=t<BR>\n" );
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document.write( "answer: the car will catch the bike in 2 hours after the cars leaves. </SPAN>\n" );
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