document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387856>Question 387856</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bicyclist leaves Bay Shore traveling at an average speed of 12 miles per hour. Three hours later, a car leaves Bay Shore, on the same route, traveling at an average speed of 30 miles per hour. How many hours after the car leaves Bay Shore will the car catch up to the cyclist? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274216 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274216\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the cyclist has a 36 mi head start (12 mph * 3 hr)\r<BR>\n" );
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document.write( "the car closes the gap at 18 mph (30 mph - 12 mph)\r<BR>\n" );
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document.write( "the car catches the cyclist after 2 hr (36 mi / 18 mph) </SPAN>\n" );
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