document.write( "Question 387892: find three consecutive odd integers such that the sum of the first and twice the second is 6 more than the third. \n" ); document.write( "
Algebra.Com's Answer #274211 by rfadrogane(214)\"\" \"About 
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find three consecutive odd integers such that the sum of the first and twice the second is 6 more than the third.
\n" ); document.write( "Sol'n:
\n" ); document.write( " let: x - the 1st integer
\n" ); document.write( " x+2 - the 2nd integer
\n" ); document.write( " x+4 - the 3rd integer
\n" ); document.write( "x+2(x+2)= (x+4)+6
\n" ); document.write( "3x+4=x+10
\n" ); document.write( "2x=10-4
\n" ); document.write( "2x=6, divide by 2 on both side
\n" ); document.write( "x=3
\n" ); document.write( "x+2=5
\n" ); document.write( "x+4=7
\n" ); document.write( "thus,the add integer are the ff.
\n" ); document.write( "3,5&7 ----answer \n" ); document.write( "
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