document.write( "Question 42272: An observer measures the angle of evevation to the top of a mountain and obtains a value of 39 degrees. After moving 100m farther away from the mountain,the angle of elevation is massured as 38.2 degrees. How tall is the mountain? \n" ); document.write( "
Algebra.Com's Answer #27420 by psbhowmick(878)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let the points C and B denote the top and the base of the mountain respectively.
\n" ); document.write( "When the person was at D, the angle of elevation was \"39%5Eo\" and when he moved to A, 100 m away from the mountain, the angle of elevation became \"38.2%5Eo\".\r
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\n" ); document.write( "\n" ); document.write( "So, in the figure, AD = 100 m; < BAC = \"38.2%5Eo\"; < BDC = \"39%5Eo\"\r
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\n" ); document.write( "\n" ); document.write( "In right-angled triangle ABC,
\n" ); document.write( "\"BC%2FAB+=+tan%2838.2%5Eo%29\"
\n" ); document.write( "or \"AB+=+BC%2F%28tan%2838.2%5Eo%29%29\" _____(1)\r
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\n" ); document.write( "\n" ); document.write( "In right-angled triangle DBC,
\n" ); document.write( "\"BC%2FDB+=+tan%2839%5Eo%29\"
\n" ); document.write( "or \"DB+=+BC%2F%28tan%2839%5Eo%29%29\" _____(2)\r
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\n" ); document.write( "\n" ); document.write( "Subtracting (2) from (1) we have
\n" ); document.write( "\"AB+-+DB+=+BC%2Ftan%2838.2%5Eo%29+-+BC%2Ftan%2839%5Eo%29\"
\n" ); document.write( "or \"AD+=+BC%28cot%2838.2%5Eo%29+-+cot%2839%5Eo%29%29\"
\n" ); document.write( "or \"BC+=+AD%2F%28cot%2838.2%5Eo%29+-+cot%2839%5Eo%29%29\"
\n" ); document.write( "or \"BC+=+100%2F%281.270773+-+1.234897%29\"
\n" ); document.write( "or BC = 2787.4 m (approx) = 2.7874 km\r
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\n" ); document.write( "\n" ); document.write( "Hence, the reqd. height of the mountain is 2.7874 km.
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