document.write( "Question 387834: log(7x+1)=log(x-2)+ 1 \n" ); document.write( "

Algebra.Com's Answer #274171 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,         
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document.write( " log(7x+1)-log(x-2)= 1
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document.write( "  10^1 = (7x+1)/(x-2)
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document.write( "  10(x-2) = 7x+1
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document.write( "  10x -20 = 7x + 1
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document.write( "       3x = 21
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document.write( "        x = 7 \n" );
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