document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387754>Question 387754</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A labourer is engaged for 20 days on the condition that he will receive Rs 60 for each day he works and will be fined Rs 5 for each day he is absent. If receives Rs 745 in all, for how many days did he remain absent?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274133 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let W = the number of days the labourer worked and A = the number of days the labourer was absent.<BR>\n" );
document.write( "Given:<BR>\n" );
document.write( "1) W+A = 20 \"A labourer was engaged for 20 days...\"<BR>\n" );
document.write( "2) 60W-5A = 745 \"...will receive (+) Rs 60 for each day he works and will be fined (-) Rs 5 for each day he is absent.\"<BR>\n" );
document.write( "Rewrite equation 1) as:<BR>\n" );
document.write( "1a) A = 20-W and substitute into equation 2) for A<BR>\n" );
document.write( "2a) 60W-5(20-W) = 745 Simplify and solve for W.<BR>\n" );
document.write( "2b) 60W-100+5W = 745<BR>\n" );
document.write( "2c) 65W = 845<BR>\n" );
document.write( "2d) W = 13 and A = 20-13 = 7.<BR>\n" );
document.write( "The labourer was absent for 7 days.   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );