document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42277>Question 42277</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sam emptied his collection of nickels and dimes on his bed. If his 46 coins were worth $3.10,how many coins of each type did he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27413 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27413\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here n are nickels and d are dimes...so we have<BR>\n" );
document.write( "n + d = 46<BR>\n" );
document.write( "and<BR>\n" );
document.write( "5n + 10d = 310 (working in cents now)<BR>\n" );
document.write( "Multiply the first eqn by 5 and subtract, we get<BR>\n" );
document.write( "5n + 10d = 310<BR>\n" );
document.write( "-(5n + 5d = 230)<BR>\n" );
document.write( "and we have<BR>\n" );
document.write( "5d = 80<BR>\n" );
document.write( "d = 16<BR>\n" );
document.write( "n = 30 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );