document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387137>Question 387137</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three numbers is 45. one number is 5 more than a second number it is also twice the third. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274127 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = one number,<BR>\n" );
document.write( "x = s + 5, and x = 2t.<BR>\n" );
document.write( "Then x + s + t = 45.  By substitution, <BR>\n" );
document.write( "x + x - 5 +x/2 = 45;<BR>\n" );
document.write( "2x + x/2 = 50;<BR>\n" );
document.write( "5x/2 = 50;<BR>\n" );
document.write( "5x = 100;<BR>\n" );
document.write( "x = 20, one number,<BR>\n" );
document.write( "s = x - 5 = 15, the second number, and <BR>\n" );
document.write( "t = x/2 = 10, the third number. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );