document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387120>Question 387120</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John is twice as old as Sarah. Three years from today, the sum of their ages will be 42. How old is John today? <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274123 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274123\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> j = 2s,<BR>\n" );
document.write( "j+3 + s+3 = 42, or j + s = 36.  Substituting the 1st equation into the last equation, we get 2s + s = 36, or 3s = 36, or s = 12, the age of Sarah now, and j = 2s = 24, the age of John. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );