document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387131>Question 387131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An investor has $7500 invested at one rate and $6200 invested at a different rate. If the second investment is at a rate 2% lower than the first, find the rate for each investment if his annual interest is $698.\r<BR>\n" );
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document.write( "This is what I have so far: \r<BR>\n" );
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document.write( " 7500x + 6200 x (x-.02) x 1 = $698\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274122 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274122\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 7500x + 6200(x-.02)= 698 ;<BR>\n" );
document.write( "7500x + 6200x - 124 = 698;<BR>\n" );
document.write( "13,700x = 822;<BR>\n" );
document.write( "x = 0.06, and x - 0.02 = 0.04. </SPAN>\n" );
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