document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387403>Question 387403</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -4x^2-3x-(x-x^2+3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274121 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274121\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-4x%5E2-3x-%28x-x%5E2%2B3%29+=+-4x%5E2-3x-x%2Bx%5E2-3+=+-3x%5E2-4x-3 ALIGN=MIDDLE  ALT=\"-4x%5E2-3x-%28x-x%5E2%2B3%29+=+-4x%5E2-3x-x%2Bx%5E2-3+=+-3x%5E2-4x-3\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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