document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387632>Question 387632</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find a pair of numbers (x,y) so that expression x^2 + y^2 - 2x gives as small a value as possible. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274118 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274118\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 + y^2 - 2x <BR>\n" );
document.write( "any number greater than or less than zero for y will make y^2 greater than zero so y must be zero.<BR>\n" );
document.write( "x^2-2x has a minimum at -b/2a<BR>\n" );
document.write( "-(-2)/2 = 1<BR>\n" );
document.write( "(1,0) Answer<BR>\n" );
document.write( " x^2 + y^2 - 2x = -1 at (1,0)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );