document.write( "Question 387717: joe has a nickles and dime that is worth $2.15. if the number of dimes was doubled and the number of nickles was increased by 28 , the value of the coins would be $6.00. How many nickles and dimes does he has? \n" ); document.write( "
Algebra.Com's Answer #274114 by josmiceli(19441)\"\" \"About 
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Let \"n\" = number of nickels
\n" ); document.write( "Let \"d\" = number of dimes
\n" ); document.write( "given:
\n" ); document.write( "(1) \"5n+%2B+10d+=+215\" (in cents)
\n" ); document.write( "(2) \"10%2A%282d%29+%2B+5%2A%28n+%2B+28%29+=+600\"
\n" ); document.write( "----------------------------------
\n" ); document.write( "There are 2 equations and 2 unknowns,
\n" ); document.write( "so it's solvable
\n" ); document.write( "(2) \"20d+%2B+5n+%2B+140+=+600\"
\n" ); document.write( "(2) \"5n+%2B+20d+=+460\"
\n" ); document.write( "Now subtract (1) from (2)
\n" ); document.write( "(2) \"5n+%2B+20d+=+460\"
\n" ); document.write( "(1) \"-5n+-+10d+=+-215\"
\n" ); document.write( "\"10d+=+245\"
\n" ); document.write( "\"d+=+24.5\" impossible
\n" ); document.write( "In (1), \"n\" has to be odd to get \"215\"
\n" ); document.write( "In (2), \"n+%2B+28\" ends up being odd again
\n" ); document.write( "and that can't give me \"600\"
\n" ); document.write( "These numbers are wrong somehow, I think.
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