document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42273>Question 42273</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The edges   of a saw  tooth are 1.39mm and 3.26mm long. The base of  the  tooth  is 2.05mm long. At what  angles  do the  edges  of the  tooth meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27409 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Because of alternate interior angles being equal, the angle at which the teeth meet equals the angle of the top of the teeth...we can find that angle using the law of cosines...<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "2.05^2 = 1.39^2 + 3.26^2 - 2(1.39)(3.26)cos C<BR>\n" );
document.write( "which leads to<BR>\n" );
document.write( "C = 22.75 degrees </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );