document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387715>Question 387715</A>: <I><SPAN STYLE=\"word-break: break-all;\"> To reproduce an old photograph, a photographer charges x dollars to make a negative, 3x/5 dollars for each of the first 10 prints, and x/5 dollars for each print in excess of 10 prints. If $45 is the total charge to make a negative and 20 prints from an old photograph, what is the value of x?\r<BR>\n" );
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document.write( "Value of x means to solve for x, right? this is how I initially set up the equation:\r<BR>\n" );
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document.write( "45=x + 3x/5 + x/5(10) which became 45=x + 3x/5 + 10x/5\r<BR>\n" );
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document.write( "this is a GRE question and i'm totally lost. Thanks for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274080 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> equation is x+(3x/5)(10)+(x/5)(10)=45\r<BR>\n" );
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document.write( "x+(3x/5)(10)+(x/5)(10)=45\r<BR>\n" );
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document.write( "x+6x+2x=45\r<BR>\n" );
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document.write( "9x=45\r<BR>\n" );
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document.write( "x=5\r<BR>\n" );
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document.write( "Answer: x=5 </SPAN>\n" );
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