document.write( "Question 42249: Solve 64^x<32^(x+2.\r
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Algebra.Com's Answer #27405 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! From 64^x < 32^(x+2), we change eveything to powers of two...we get \n" ); document.write( "(2^6)^x < (2^5)^(x+2) \n" ); document.write( "2^(6x) < 2^(5x+10) and then \n" ); document.write( "6x < 5x + 10 \n" ); document.write( "x < 10 \n" ); document.write( " |