document.write( "Question 387634: a train is going to a place B and the velocity is 80 km/h. After half an hour, another train leaves for B and its velocity is 100 km/h. both trains arrive in B at the same time. what is the lengh of the route ? \r
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document.write( "Please tell me if this solution is good enough!\r
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document.write( "S1: speed of train 1
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document.write( "S2: speed of train 2
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document.write( "D1 = distance travelled by train 1
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document.write( "D2 = distance travelled by train 2
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document.write( "t1 : time it took train 1 to get at B
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document.write( "t2 : time it took train 2(which was late by 1/2 h) to get at B
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document.write( "When both trains arrive at place B, they would have travelled the same distance and thus: D1 = D2
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document.write( " S1 * t1 = S2 * t2
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document.write( " 80 * t1 = 100 * (t1 - 1/2)
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document.write( " 80t1 = 100t1 - 50
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document.write( " t1 = 2.5 hours
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document.write( "so the D1 = 80 * 2.5 = 200 km
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document.write( "also D2 = 100 * (2.5 - 0.5) = 200 km \n" );
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Algebra.Com's Answer #274032 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "Your answer of 200 km is correct!\r \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Let x = time it takes for 80km/hr train to get to B \n" ); document.write( "then \n" ); document.write( "x- 1/2 = time it takes for 100km/hr train to get to B\r \n" ); document.write( "\n" ); document.write( "80x = 100(x-1/2) \n" ); document.write( "multiplying both sides by 2: \n" ); document.write( "160x = 100(2x-1) \n" ); document.write( "160x = 200x-100 \n" ); document.write( "0 = 40x-100 \n" ); document.write( "100 = 40x \n" ); document.write( "100/40 = x \n" ); document.write( "5/2 hours = x\r \n" ); document.write( "\n" ); document.write( "Distance then is: \n" ); document.write( "80(5/2) = 40*5 = 200 km\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |