document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=42256>Question 42256</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131400592/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Joan is the owner of Starbucks.  She has many varieties of coffee in the shop including a Kona variety that sells for $6.20 per pound and an amaretto coffee that sells for $5.80 a pound.  She finds that by mixing these two blends she creates a coffee that sells well.  If she uses 18 pounds of amaretto coffee in the blend and wishes to sell the mixture at $6.10 per pound, how many pounds of the Kona coffee should she mix with the amaretto coffee? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27403 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27403\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let k be the amount of Kona and a be the amount of amaretto.<BR>\n" );
document.write( "The setup looks like this:<BR>\n" );
document.write( "6.20k + 5.80a = 6.10(k+a)<BR>\n" );
document.write( "6.20k + 5.80(18) = 6.10(k + 18)<BR>\n" );
document.write( "620k + 580(18) = 610(k + 18)<BR>\n" );
document.write( "620k + 10440 = 610k + 10980<BR>\n" );
document.write( "10k = 540<BR>\n" );
document.write( "k = 54 pounds </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );