document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387571>Question 387571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is a honey bee and a train 100Kms apart. The train travels at 40Km/Hr and bee at 60Km/hr. Both start from opposite direction. If the honeybee returns back to the starting point after colliding with the train. It again returns back after meeting the starting position and this process continues till the train reach the position at which the honeybee started. Find the total distance travelled by the honeybee.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #274025 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=274025\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance(d) equals Rate(r) times Time(t) or d=rt;  r=d/t and t=d/r<BR>\n" );
document.write( "It takes the train 100/40=2.5 hours to get to the bee's starting point.<BR>\n" );
document.write( "In 2.5 hours, the bee travels 60*(2.5)=150 km<BR>\n" );
document.write( "This assumes the bee does not lose any time making u-turns\r<BR>\n" );
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document.write( "Hope this helps----ptaylor<BR>\n" );
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