document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387503>Question 387503</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you graph y=-1/2x to the third power? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273965 by </B><A HREF=/tutors/aboutme.mpl?userid=Jk22><B>Jk22(389)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jk22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jk22><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273965\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let y(x)=-1/2x^3<BR>\n" );
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document.write( "behaviour at infinity : <BR>\n" );
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document.write( "x->+00 => y->-oo<BR>\n" );
document.write( "x->-oo => y->+oo<BR>\n" );
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document.write( "y'(x)=-3/2x^2<BR>\n" );
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document.write( "y'=0 => x=0 => stationary point at x=0, y=0<BR>\n" );
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document.write( "y''(0)=-3x => saddle point at x=0<BR>\n" );
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document.write( "hence the graph is : \r<BR>\n" );
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