document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387511>Question 387511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to Write an equation of the line perpendicular to the line given by 2x + 3y = 7 and having the same y-intercept as the line given by 5x + 2y = 10. I know that I need to get the opposite reciprocal slope from the first equation and use the y-intercept from the second equation and put them together but I am still confused and need to be walked through what I need to do.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273943 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> change the to slope intercept form<BR>\n" );
document.write( "2x+3y=7<BR>\n" );
document.write( "3y=-2x+7<BR>\n" );
document.write( "y=-2/3x+7/3<BR>\n" );
document.write( "y=-2/3x+2 1/3<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "5x+2y=10<BR>\n" );
document.write( "2y=-5x+10<BR>\n" );
document.write( "y=-5/2x+5<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "m=-2/3<BR>\n" );
document.write( "b=5<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "can you go from here? </SPAN>\n" );
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