document.write( "Question 387467: Can you help me solve this?
\n" ); document.write( "sr = square root\r
\n" ); document.write( "\n" ); document.write( "sr x + 12 = x
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Algebra.Com's Answer #273876 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
sr x + 12 = x
\n" ); document.write( "----
\n" ); document.write( "sqrt(x) + 12 = x
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\n" ); document.write( "Rearrange:
\n" ); document.write( "x + sqrt(x) + 12 = 0
\n" ); document.write( "---
\n" ); document.write( "Factor:
\n" ); document.write( "(sqrt(x)+4)(sqrt(x)-3) = 0
\n" ); document.write( "----
\n" ); document.write( "sqrt(x) = 4 or sqrt(x) = 3
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\n" ); document.write( "x = 16 or x = 9
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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