document.write( "Question 387441: It is possible for a quadratic equation to have no real-number solutions.
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\n" ); document.write( "t2 + 10 = 6t \n" ); document.write( "
Algebra.Com's Answer #273844 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

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document.write( "Hi,   
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document.write( " Yes, when b^2 - 4ac < 0 in the quadratic equaton ax^2 + bx + c = 0 
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document.write( "that will result in \"sqrt%28b%5E2+-+4ac+%29\" being an imaginary number.
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document.write( "solving using the quadratic equation
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document.write( "t^2 - 6t + 10 = 0
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document.write( "  \"t+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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document.write( "  \"t+=+%286+%2B-+sqrt%28+-4%29%29%2F%282%29+\"
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document.write( "  \"t+=+%286+%2B-+2i%29%2F%282%29+\"
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document.write( "  \"t+=+3+%2B-+i%29+\"
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document.write( "this quadraic equation has no real-number solutions \n" );
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