document.write( "Question 387441: It is possible for a quadratic equation to have no real-number solutions.
\n" ); document.write( "Solve
\n" ); document.write( "t2 + 10 = 6t
\n" ); document.write( "

Algebra.Com's Answer #273842 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Yes, it's possible. eg, x^2 + 4 = 0
\n" ); document.write( "-----------
\n" ); document.write( "t^2 + 10 = 6t
\n" ); document.write( "t^2 - 6t + 10 = 0
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-6x%2B10+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-6%29%5E2-4%2A1%2A10=-4\".
\n" ); document.write( "
\n" ); document.write( " The discriminant -4 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

\n" ); document.write( "
\n" ); document.write( " In the field of imaginary numbers, the square root of -4 is + or - \"sqrt%28+4%29+=+2\".
\n" ); document.write( "
\n" ); document.write( " The solution is \"x%5B12%5D+=+%28--6%2B-i%2Asqrt%28+-4+%29%29%2F2%5C1+=++%28--6%2B-i%2A2%29%2F2%5C1+\", or
\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-6%2Ax%2B10+%29\"

\n" ); document.write( "\n" ); document.write( "---------------
\n" ); document.write( "t = 3 ± i
\n" ); document.write( "No real number solutions.
\n" ); document.write( "
\n" ); document.write( "
\n" );