document.write( "Question 387434: Hope's age in 1951 is H: Gable's age in 1951 is G; and that Fonda's age in 1951 is F. Fonda was 2 years younger than Hope. Gable was two years older than Hope. Th sum of their ages was 144.\r
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Algebra.Com's Answer #273837 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Let x, (x-2) and (x+2) represent Hope's , Fonda's and Gable's ages respectively
\n" ); document.write( "Question states***
\n" ); document.write( " x + (x-2) + (x+2) = 144
\n" ); document.write( "solving for x
\n" ); document.write( " 3x = 144
\n" ); document.write( " x = 48, Hope's age. Fonda's was 46 and Gable's 50\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 48 + 46 + 50 = 144\r
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