document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=387379>Question 387379</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a ball is thrown into the air from a height of 3 feet with an initial velocity of 20 feet per second and is caught at a height of 6 feet. Find the maximum height of the ball and how long it takes to hit the ground. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #273817 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=273817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  a ball is thrown into the air from a height of 3 feet with an initial velocity of 20 feet per second and is caught at a height of 6 feet. Find the maximum height of the ball and how long it takes to hit the ground.<BR>\n" );
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document.write( "h(t) = -16t^2+20t+3<BR>\n" );
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document.write( "Max height occurs when t = -b/(2a) = -20/(2*-16) = 5/8 sec.<BR>\n" );
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document.write( "Height at that time: h(5/8) = 9.25 ft.<BR>\n" );
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document.write( "Ground time:<BR>\n" );
document.write( "Solve -16t^2+20t+3 = 0 for \"t\":<BR>\n" );
document.write( "t = [-20 +- sqrt(20^2-4*-16*3)]/-32<BR>\n" );
document.write( "---<BR>\n" );
document.write( "t = [-20 - sqrt(592)]/-32<BR>\n" );
document.write( "t = 1.3853 seconds<BR>\n" );
document.write( "============================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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