document.write( "Question 387378: the perimiter of a right triangle is 12. the lengths of the legs of the triangle are 3 and x. the length of the hypotenuse is y.
\n" ); document.write( "how can i set up a system of equation that could be used to find the hypotenuse and the other of the right triangle?
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Algebra.Com's Answer #273816 by stanbon(75887)\"\" \"About 
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the perimeter of a right triangle is 12.
\n" ); document.write( "the lengths of the legs of the triangle are 3 and x.
\n" ); document.write( "the length of the hypotenuse is y.
\n" ); document.write( "how can i set up a system of equation that could be used to find the hypotenuse and the other of the right triangle?
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\n" ); document.write( "Express the hypotenuse in terms of \"x\" using Pythagoras.
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\n" ); document.write( "y^2 = 3^2 + x^2
\n" ); document.write( "y = sqrt(9+x^2)
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\n" ); document.write( "Then the perimeter is 3 + x + sqrt(9+x^2) = 12
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x + sqrt(9+x^2) = 9
\n" ); document.write( "sqrt(9+x^2) = 9-x
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\n" ); document.write( "Square both sides to get:
\n" ); document.write( "9+x^2 = 81-18x+x^2
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\n" ); document.write( "9 = 81-18x
\n" ); document.write( "18x = 72
\n" ); document.write( "x = 4
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\n" ); document.write( "The sides are 3,4,y
\n" ); document.write( "y = sqrt(9+x^2) = sqrt(9+16) = 5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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